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3x-2(x+1)=-2(2x+1)
We move all terms to the left:
3x-2(x+1)-(-2(2x+1))=0
We multiply parentheses
3x-2x-(-2(2x+1))-2=0
We calculate terms in parentheses: -(-2(2x+1)), so:We add all the numbers together, and all the variables
-2(2x+1)
We multiply parentheses
-4x-2
Back to the equation:
-(-4x-2)
x-(-4x-2)-2=0
We get rid of parentheses
x+4x+2-2=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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