3x-2(x+1)=6x-17+20

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Solution for 3x-2(x+1)=6x-17+20 equation: 



3x-2(x+1)=6x-17+20

We move all terms to the left:

3x-2(x+1)-(6x-17+20)=0

We add all the numbers together, and all the variables

3x-2(x+1)-(6x+3)=0

We multiply parentheses

3x-2x-(6x+3)-2=0

We get rid of parentheses

3x-2x-6x-3-2=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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