3x-2(x+10)=7x-5(x+2)

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Solution for 3x-2(x+10)=7x-5(x+2) equation: 



3x-2(x+10)=7x-5(x+2)

We move all terms to the left:

3x-2(x+10)-(7x-5(x+2))=0

We multiply parentheses

3x-2x-(7x-5(x+2))-20=0



We calculate terms in parentheses: -(7x-5(x+2)), so:

7x-5(x+2)

We multiply parentheses

7x-5x-10

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

x-(2x-10)-20=0

We get rid of parentheses

x-2x+10-20=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10

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