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3x-2(x+2)+4=7(3x-3)+2x-(5-x)+3
We move all terms to the left:
3x-2(x+2)+4-(7(3x-3)+2x-(5-x)+3)=0
We add all the numbers together, and all the variables
3x-2(x+2)-(7(3x-3)+2x-(-1x+5)+3)+4=0
We multiply parentheses
3x-2x-(7(3x-3)+2x-(-1x+5)+3)-4+4=0
We calculate terms in parentheses: -(7(3x-3)+2x-(-1x+5)+3), so:We add all the numbers together, and all the variables
7(3x-3)+2x-(-1x+5)+3
We add all the numbers together, and all the variables
2x+7(3x-3)-(-1x+5)+3
We multiply parentheses
2x+21x-(-1x+5)-21+3
We get rid of parentheses
2x+21x+1x-5-21+3
We add all the numbers together, and all the variables
24x-23
Back to the equation:
-(24x-23)
x-(24x-23)=0
We get rid of parentheses
x-24x+23=0
We add all the numbers together, and all the variables
-23x+23=0
We move all terms containing x to the left, all other terms to the right
-23x=-23
x=-23/-23
x=1
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