3x-2(x+2)=4(x+3)+7

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Solution for 3x-2(x+2)=4(x+3)+7 equation: 



3x-2(x+2)=4(x+3)+7

We move all terms to the left:

3x-2(x+2)-(4(x+3)+7)=0

We multiply parentheses

3x-2x-(4(x+3)+7)-4=0



We calculate terms in parentheses: -(4(x+3)+7), so:

4(x+3)+7

We multiply parentheses

4x+12+7

We add all the numbers together, and all the variables

4x+19

Back to the equation:

-(4x+19)



We add all the numbers together, and all the variables

x-(4x+19)-4=0

We get rid of parentheses

x-4x-19-4=0

We add all the numbers together, and all the variables

-3x-23=0

We move all terms containing x to the left, all other terms to the right

-3x=23

x=23/-3

x=-7+2/3

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