3x-2(x+2)=4(x-3)

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Solution for 3x-2(x+2)=4(x-3) equation: 



3x-2(x+2)=4(x-3)

We move all terms to the left:

3x-2(x+2)-(4(x-3))=0

We multiply parentheses

3x-2x-(4(x-3))-4=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

x-(4x-12)-4=0

We get rid of parentheses

x-4x+12-4=0

We add all the numbers together, and all the variables

-3x+8=0

We move all terms containing x to the left, all other terms to the right

-3x=-8

x=-8/-3

x=2+2/3

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