3x-2(x+3)=4(x-2)

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Solution for 3x-2(x+3)=4(x-2) equation: 



3x-2(x+3)=4(x-2)

We move all terms to the left:

3x-2(x+3)-(4(x-2))=0

We multiply parentheses

3x-2x-(4(x-2))-6=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

x-(4x-8)-6=0

We get rid of parentheses

x-4x+8-6=0

We add all the numbers together, and all the variables

-3x+2=0

We move all terms containing x to the left, all other terms to the right

-3x=-2

x=-2/-3

x=2/3

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