3x-2(x+5)=10x-4(3x-1)+7

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Solution for 3x-2(x+5)=10x-4(3x-1)+7 equation: 



3x-2(x+5)=10x-4(3x-1)+7

We move all terms to the left:

3x-2(x+5)-(10x-4(3x-1)+7)=0

We multiply parentheses

3x-2x-(10x-4(3x-1)+7)-10=0



We calculate terms in parentheses: -(10x-4(3x-1)+7), so:

10x-4(3x-1)+7

We multiply parentheses

10x-12x+4+7

We add all the numbers together, and all the variables

-2x+11

Back to the equation:

-(-2x+11)



We add all the numbers together, and all the variables

x-(-2x+11)-10=0

We get rid of parentheses

x+2x-11-10=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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