3x-2(x-10)=02(4x)-7

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Solution for 3x-2(x-10)=02(4x)-7 equation: 



3x-2(x-10)=02(4x)-7

We move all terms to the left:

3x-2(x-10)-(02(4x)-7)=0

We multiply parentheses

3x-2x-(024x-7)+20=0

We get rid of parentheses

3x-2x-024x+7+20=0

We add all the numbers together, and all the variables

-23x+27=0

We move all terms containing x to the left, all other terms to the right

-23x=-27

x=-27/-23

x=1+4/23

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