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3x-2(x-3)+5x=2+3(x-7)
We move all terms to the left:
3x-2(x-3)+5x-(2+3(x-7))=0
We add all the numbers together, and all the variables
8x-2(x-3)-(2+3(x-7))=0
We multiply parentheses
8x-2x-(2+3(x-7))+6=0
We calculate terms in parentheses: -(2+3(x-7)), so:We add all the numbers together, and all the variables
2+3(x-7)
determiningTheFunctionDomain 3(x-7)+2
We multiply parentheses
3x-21+2
We add all the numbers together, and all the variables
3x-19
Back to the equation:
-(3x-19)
6x-(3x-19)+6=0
We get rid of parentheses
6x-3x+19+6=0
We add all the numbers together, and all the variables
3x+25=0
We move all terms containing x to the left, all other terms to the right
3x=-25
x=-25/3
x=-8+1/3
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