3x-2(x-4)+10=12

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Solution for 3x-2(x-4)+10=12 equation: 



3x-2(x-4)+10=12

We move all terms to the left:

3x-2(x-4)+10-(12)=0

We add all the numbers together, and all the variables

3x-2(x-4)-2=0

We multiply parentheses

3x-2x+8-2=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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