3x-2(x-4)+10=12

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Solution for 3x-2(x-4)+10=12 equation:



3x-2(x-4)+10=12
We move all terms to the left:
3x-2(x-4)+10-(12)=0
We add all the numbers together, and all the variables
3x-2(x-4)-2=0
We multiply parentheses
3x-2x+8-2=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6

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