3x-2(x-4)=(x-4)*5

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Solution for 3x-2(x-4)=(x-4)*5 equation: 



3x-2(x-4)=(x-4)*5

We move all terms to the left:

3x-2(x-4)-((x-4)*5)=0

We multiply parentheses

3x-2x-((x-4)*5)+8=0



We calculate terms in parentheses: -((x-4)*5), so:

(x-4)*5

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

x-(5x-20)+8=0

We get rid of parentheses

x-5x+20+8=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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