3x-2(x-5)=2(x-3)-8

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Solution for 3x-2(x-5)=2(x-3)-8 equation: 



3x-2(x-5)=2(x-3)-8

We move all terms to the left:

3x-2(x-5)-(2(x-3)-8)=0

We multiply parentheses

3x-2x-(2(x-3)-8)+10=0



We calculate terms in parentheses: -(2(x-3)-8), so:

2(x-3)-8

We multiply parentheses

2x-6-8

We add all the numbers together, and all the variables

2x-14

Back to the equation:

-(2x-14)



We add all the numbers together, and all the variables

x-(2x-14)+10=0

We get rid of parentheses

x-2x+14+10=0

We add all the numbers together, and all the variables

-1x+24=0

We move all terms containing x to the left, all other terms to the right

-x=-24

x=-24/-1

x=+24

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