3x-2(x-8)=1x+16

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Solution for 3x-2(x-8)=1x+16 equation: 



3x-2(x-8)=1x+16

We move all terms to the left:

3x-2(x-8)-(1x+16)=0

We add all the numbers together, and all the variables

3x-2(x-8)-(x+16)=0

We multiply parentheses

3x-2x-(x+16)+16=0

We get rid of parentheses

3x-2x-x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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