3x-2+4(x-5)=10

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Solution for 3x-2+4(x-5)=10 equation: 



3x-2+4(x-5)=10

We move all terms to the left:

3x-2+4(x-5)-(10)=0

We add all the numbers together, and all the variables

3x+4(x-5)-12=0

We multiply parentheses

3x+4x-20-12=0

We add all the numbers together, and all the variables

7x-32=0

We move all terms containing x to the left, all other terms to the right

7x=32

x=32/7

x=4+4/7

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