3x-2-1=8(x+1)+1

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Solution for 3x-2-1=8(x+1)+1 equation: 



3x-2-1=8(x+1)+1

We move all terms to the left:

3x-2-1-(8(x+1)+1)=0

We add all the numbers together, and all the variables

3x-(8(x+1)+1)-3=0



We calculate terms in parentheses: -(8(x+1)+1), so:

8(x+1)+1

We multiply parentheses

8x+8+1

We add all the numbers together, and all the variables

8x+9

Back to the equation:

-(8x+9)



We get rid of parentheses

3x-8x-9-3=0

We add all the numbers together, and all the variables

-5x-12=0

We move all terms containing x to the left, all other terms to the right

-5x=12

x=12/-5

x=-2+2/5

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