3x-2-3(-1+2x)=2-2(x+1)

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Solution for 3x-2-3(-1+2x)=2-2(x+1) equation: 



3x-2-3(-1+2x)=2-2(x+1)

We move all terms to the left:

3x-2-3(-1+2x)-(2-2(x+1))=0

We add all the numbers together, and all the variables

3x-3(2x-1)-(2-2(x+1))-2=0

We multiply parentheses

3x-6x-(2-2(x+1))+3-2=0



We calculate terms in parentheses: -(2-2(x+1)), so:

2-2(x+1)

determiningTheFunctionDomain
-2(x+1)+2

We multiply parentheses

-2x-2+2

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We add all the numbers together, and all the variables

-3x-(-2x)+1=0

We get rid of parentheses

-3x+2x+1=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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