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3x-2/3x+10=7
We move all terms to the left:
3x-2/3x+10-(7)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3x-2/3x+3=0
We multiply all the terms by the denominator
3x*3x+3*3x-2=0
Wy multiply elements
9x^2+9x-2=0
a = 9; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·9·(-2)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{17}}{2*9}=\frac{-9-3\sqrt{17}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{17}}{2*9}=\frac{-9+3\sqrt{17}}{18} $
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