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3x-2/5x=-4x
We move all terms to the left:
3x-2/5x-(-4x)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3x-2/5x+4x=0
We multiply all the terms by the denominator
3x*5x+4x*5x-2=0
Wy multiply elements
15x^2+20x^2-2=0
We add all the numbers together, and all the variables
35x^2-2=0
a = 35; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·35·(-2)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{70}}{2*35}=\frac{0-2\sqrt{70}}{70} =-\frac{2\sqrt{70}}{70} =-\frac{\sqrt{70}}{35} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{70}}{2*35}=\frac{0+2\sqrt{70}}{70} =\frac{2\sqrt{70}}{70} =\frac{\sqrt{70}}{35} $
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