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3x-2/7x=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
3x*7x-2=0
Wy multiply elements
21x^2-2=0
a = 21; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·21·(-2)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{42}}{2*21}=\frac{0-2\sqrt{42}}{42} =-\frac{2\sqrt{42}}{42} =-\frac{\sqrt{42}}{21} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{42}}{2*21}=\frac{0+2\sqrt{42}}{42} =\frac{2\sqrt{42}}{42} =\frac{\sqrt{42}}{21} $
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