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3x-2/x=6+4x
We move all terms to the left:
3x-2/x-(6+4x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3x-2/x-(4x+6)=0
We get rid of parentheses
3x-2/x-4x-6=0
We multiply all the terms by the denominator
3x*x-4x*x-6*x-2=0
We add all the numbers together, and all the variables
-6x+3x*x-4x*x-2=0
Wy multiply elements
3x^2-4x^2-6x-2=0
We add all the numbers together, and all the variables
-1x^2-6x-2=0
a = -1; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·(-1)·(-2)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{7}}{2*-1}=\frac{6-2\sqrt{7}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{7}}{2*-1}=\frac{6+2\sqrt{7}}{-2} $
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