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3x-20=70/6x
We move all terms to the left:
3x-20-(70/6x)=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+70/6x)-20=0
We get rid of parentheses
3x-70/6x-20=0
We multiply all the terms by the denominator
3x*6x-20*6x-70=0
Wy multiply elements
18x^2-120x-70=0
a = 18; b = -120; c = -70;
Δ = b2-4ac
Δ = -1202-4·18·(-70)
Δ = 19440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19440}=\sqrt{1296*15}=\sqrt{1296}*\sqrt{15}=36\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-36\sqrt{15}}{2*18}=\frac{120-36\sqrt{15}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+36\sqrt{15}}{2*18}=\frac{120+36\sqrt{15}}{36} $
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