3x-3(4+2x)=78

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Solution for 3x-3(4+2x)=78 equation: 



3x-3(4+2x)=78

We move all terms to the left:

3x-3(4+2x)-(78)=0

We add all the numbers together, and all the variables

3x-3(2x+4)-78=0

We multiply parentheses

3x-6x-12-78=0

We add all the numbers together, and all the variables

-3x-90=0

We move all terms containing x to the left, all other terms to the right

-3x=90

x=90/-3

x=-30

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