3x-3(4-3x)=4(x-3)-40

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Solution for 3x-3(4-3x)=4(x-3)-40 equation: 



3x-3(4-3x)=4(x-3)-40

We move all terms to the left:

3x-3(4-3x)-(4(x-3)-40)=0

We add all the numbers together, and all the variables

3x-3(-3x+4)-(4(x-3)-40)=0

We multiply parentheses

3x+9x-(4(x-3)-40)-12=0



We calculate terms in parentheses: -(4(x-3)-40), so:

4(x-3)-40

We multiply parentheses

4x-12-40

We add all the numbers together, and all the variables

4x-52

Back to the equation:

-(4x-52)



We add all the numbers together, and all the variables

12x-(4x-52)-12=0

We get rid of parentheses

12x-4x+52-12=0

We add all the numbers together, and all the variables

8x+40=0

We move all terms containing x to the left, all other terms to the right

8x=-40

x=-40/8

x=-5

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