3x-3(x-2)+(y-4)=

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Solution for 3x-3(x-2)+(y-4)= equation:


Simplifying
3x + -3(x + -2) + (y + -4) = 0

Reorder the terms:
3x + -3(-2 + x) + (y + -4) = 0
3x + (-2 * -3 + x * -3) + (y + -4) = 0
3x + (6 + -3x) + (y + -4) = 0

Reorder the terms:
3x + 6 + -3x + (-4 + y) = 0

Remove parenthesis around (-4 + y)
3x + 6 + -3x + -4 + y = 0

Reorder the terms:
6 + -4 + 3x + -3x + y = 0

Combine like terms: 6 + -4 = 2
2 + 3x + -3x + y = 0

Combine like terms: 3x + -3x = 0
2 + 0 + y = 0
2 + y = 0

Solving
2 + y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2

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