3x-3(x-2)=2(4+x)-12

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Solution for 3x-3(x-2)=2(4+x)-12 equation: 



3x-3(x-2)=2(4+x)-12

We move all terms to the left:

3x-3(x-2)-(2(4+x)-12)=0

We add all the numbers together, and all the variables

3x-3(x-2)-(2(x+4)-12)=0

We multiply parentheses

3x-3x-(2(x+4)-12)+6=0



We calculate terms in parentheses: -(2(x+4)-12), so:

2(x+4)-12

We multiply parentheses

2x+8-12

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

-(2x-4)+6=0

We get rid of parentheses

-2x+4+6=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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