3x-3+6=2(x+2)+1

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Solution for 3x-3+6=2(x+2)+1 equation: 



3x-3+6=2(x+2)+1

We move all terms to the left:

3x-3+6-(2(x+2)+1)=0

We add all the numbers together, and all the variables

3x-(2(x+2)+1)+3=0



We calculate terms in parentheses: -(2(x+2)+1), so:

2(x+2)+1

We multiply parentheses

2x+4+1

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

3x-2x-5+3=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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