3x-3+7=4x+2-3(2+x)

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Solution for 3x-3+7=4x+2-3(2+x) equation: 



3x-3+7=4x+2-3(2+x)

We move all terms to the left:

3x-3+7-(4x+2-3(2+x))=0

We add all the numbers together, and all the variables

3x-(4x+2-3(x+2))-3+7=0

We add all the numbers together, and all the variables

3x-(4x+2-3(x+2))+4=0



We calculate terms in parentheses: -(4x+2-3(x+2)), so:

4x+2-3(x+2)

determiningTheFunctionDomain
4x-3(x+2)+2

We multiply parentheses

4x-3x-6+2

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)



We get rid of parentheses

3x-x+4+4=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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