3x-3+7x=3(6x-3)+4

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Solution for 3x-3+7x=3(6x-3)+4 equation: 



3x-3+7x=3(6x-3)+4

We move all terms to the left:

3x-3+7x-(3(6x-3)+4)=0

We add all the numbers together, and all the variables

10x-(3(6x-3)+4)-3=0



We calculate terms in parentheses: -(3(6x-3)+4), so:

3(6x-3)+4

We multiply parentheses

18x-9+4

We add all the numbers together, and all the variables

18x-5

Back to the equation:

-(18x-5)



We get rid of parentheses

10x-18x+5-3=0

We add all the numbers together, and all the variables

-8x+2=0

We move all terms containing x to the left, all other terms to the right

-8x=-2

x=-2/-8

x=1/4

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