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3x-3+x=-(x-12)
We move all terms to the left:
3x-3+x-(-(x-12))=0
We add all the numbers together, and all the variables
4x-(-(x-12))-3=0
We calculate terms in parentheses: -(-(x-12)), so:We get rid of parentheses
-(x-12)
We get rid of parentheses
-x+12
We add all the numbers together, and all the variables
-1x+12
Back to the equation:
-(-1x+12)
4x+1x-12-3=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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