3x-3-8=7(1+x)+2

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Solution for 3x-3-8=7(1+x)+2 equation: 



3x-3-8=7(1+x)+2

We move all terms to the left:

3x-3-8-(7(1+x)+2)=0

We add all the numbers together, and all the variables

3x-(7(x+1)+2)-3-8=0

We add all the numbers together, and all the variables

3x-(7(x+1)+2)-11=0



We calculate terms in parentheses: -(7(x+1)+2), so:

7(x+1)+2

We multiply parentheses

7x+7+2

We add all the numbers together, and all the variables

7x+9

Back to the equation:

-(7x+9)



We get rid of parentheses

3x-7x-9-11=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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