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3x-35+2x=5(x-7)
We move all terms to the left:
3x-35+2x-(5(x-7))=0
We add all the numbers together, and all the variables
5x-(5(x-7))-35=0
We calculate terms in parentheses: -(5(x-7)), so:We get rid of parentheses
5(x-7)
We multiply parentheses
5x-35
Back to the equation:
-(5x-35)
5x-5x+35-35=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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