3x-3=(3/4)(2x+12)

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Solution for 3x-3=(3/4)(2x+12) equation: 


x in (-oo:+oo)

3*x-3 = (3/4)*(2*x+12) // - (3/4)*(2*x+12)

3*x-((3/4)*(2*x+12))-3 = 0

(-3/4)*(2*x+12)+3*x-3 = 0

3*x-3/4*(2*x+12)-3 = 0

3*x-3/4*(2*x+12)-3 = 0

3/2*x-9-3 = 0

3/2*x-12 = 0

3/2*x-12 = 0

3/2*x-12 = 0 // + 12

3/2*x = 12 // : 3/2

x = 12/3/2

x = 8

x = 8

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