3x-3=2(x-10)+22

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Solution for 3x-3=2(x-10)+22 equation: 



3x-3=2(x-10)+22

We move all terms to the left:

3x-3-(2(x-10)+22)=0



We calculate terms in parentheses: -(2(x-10)+22), so:

2(x-10)+22

We multiply parentheses

2x-20+22

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

3x-2x-2-3=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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