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3x-3=9(5x-1/3)
We move all terms to the left:
3x-3-(9(5x-1/3))=0
We add all the numbers together, and all the variables
3x-(9(+5x-1/3))-3=0
We multiply all the terms by the denominator
3x*3))-(9(+5x-1-3*3))=0
We add all the numbers together, and all the variables
3x*3))-(9(5x-10))=0
We add all the numbers together, and all the variables
3x*3))-(9(5x=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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