3x-4(1+4x)=8+3x

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Solution for 3x-4(1+4x)=8+3x equation: 



3x-4(1+4x)=8+3x

We move all terms to the left:

3x-4(1+4x)-(8+3x)=0

We add all the numbers together, and all the variables

3x-4(4x+1)-(3x+8)=0

We multiply parentheses

3x-16x-(3x+8)-4=0

We get rid of parentheses

3x-16x-3x-8-4=0

We add all the numbers together, and all the variables

-16x-12=0

We move all terms containing x to the left, all other terms to the right

-16x=12

x=12/-16

x=-3/4

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