3x-4(2-3x)-16=5-2(4x+3)

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Solution for 3x-4(2-3x)-16=5-2(4x+3) equation: 



3x-4(2-3x)-16=5-2(4x+3)

We move all terms to the left:

3x-4(2-3x)-16-(5-2(4x+3))=0

We add all the numbers together, and all the variables

3x-4(-3x+2)-(5-2(4x+3))-16=0

We multiply parentheses

3x+12x-(5-2(4x+3))-8-16=0



We calculate terms in parentheses: -(5-2(4x+3)), so:

5-2(4x+3)

determiningTheFunctionDomain
-2(4x+3)+5

We multiply parentheses

-8x-6+5

We add all the numbers together, and all the variables

-8x-1

Back to the equation:

-(-8x-1)



We add all the numbers together, and all the variables

15x-(-8x-1)-24=0

We get rid of parentheses

15x+8x+1-24=0

We add all the numbers together, and all the variables

23x-23=0

We move all terms containing x to the left, all other terms to the right

23x=23

x=23/23

x=1

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