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3x-4(2-5x)=(x+5)-11
We move all terms to the left:
3x-4(2-5x)-((x+5)-11)=0
We add all the numbers together, and all the variables
3x-4(-5x+2)-((x+5)-11)=0
We multiply parentheses
3x+20x-((x+5)-11)-8=0
We calculate terms in parentheses: -((x+5)-11), so:We add all the numbers together, and all the variables
(x+5)-11
We get rid of parentheses
x+5-11
We add all the numbers together, and all the variables
x-6
Back to the equation:
-(x-6)
23x-(x-6)-8=0
We get rid of parentheses
23x-x+6-8=0
We add all the numbers together, and all the variables
22x-2=0
We move all terms containing x to the left, all other terms to the right
22x=2
x=2/22
x=1/11
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