3x-4(2-5x)=7(x+5)-11

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Solution for 3x-4(2-5x)=7(x+5)-11 equation: 



3x-4(2-5x)=7(x+5)-11

We move all terms to the left:

3x-4(2-5x)-(7(x+5)-11)=0

We add all the numbers together, and all the variables

3x-4(-5x+2)-(7(x+5)-11)=0

We multiply parentheses

3x+20x-(7(x+5)-11)-8=0



We calculate terms in parentheses: -(7(x+5)-11), so:

7(x+5)-11

We multiply parentheses

7x+35-11

We add all the numbers together, and all the variables

7x+24

Back to the equation:

-(7x+24)



We add all the numbers together, and all the variables

23x-(7x+24)-8=0

We get rid of parentheses

23x-7x-24-8=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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