3x-4(2-x)=7(x+)1

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Solution for 3x-4(2-x)=7(x+)1 equation: 



3x-4(2-x)=7(x+)1

We move all terms to the left:

3x-4(2-x)-(7(x+)1)=0

We add all the numbers together, and all the variables

3x-4(-1x+2)-(7(+x)1)=0

We multiply parentheses

3x+4x-(7(+x)1)-8=0



We calculate terms in parentheses: -(7(+x)1), so:

7(+x)1

We multiply parentheses

7x

Back to the equation:

-(7x)



We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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