3x-4(2-x)=7(x+)1

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Solution for 3x-4(2-x)=7(x+)1 equation:



3x-4(2-x)=7(x+)1
We move all terms to the left:
3x-4(2-x)-(7(x+)1)=0
We add all the numbers together, and all the variables
3x-4(-1x+2)-(7(+x)1)=0
We multiply parentheses
3x+4x-(7(+x)1)-8=0
We calculate terms in parentheses: -(7(+x)1), so:
7(+x)1
We multiply parentheses
7x
Back to the equation:
-(7x)
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation

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