3x-4(2x+5)=3(x-20)=10

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Solution for 3x-4(2x+5)=3(x-20)=10 equation: 



3x-4(2x+5)=3(x-20)=10

We move all terms to the left:

3x-4(2x+5)-(3(x-20))=0

We multiply parentheses

3x-8x-(3(x-20))-20=0



We calculate terms in parentheses: -(3(x-20)), so:

3(x-20)

We multiply parentheses

3x-60

Back to the equation:

-(3x-60)



We add all the numbers together, and all the variables

-5x-(3x-60)-20=0

We get rid of parentheses

-5x-3x+60-20=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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