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3x-4(2x-1)=3(x+2)
We move all terms to the left:
3x-4(2x-1)-(3(x+2))=0
We multiply parentheses
3x-8x-(3(x+2))+4=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
-5x-(3x+6)+4=0
We get rid of parentheses
-5x-3x-6+4=0
We add all the numbers together, and all the variables
-8x-2=0
We move all terms containing x to the left, all other terms to the right
-8x=2
x=2/-8
x=-1/4
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