3x-4(2x-3)=2(2x+1)+6

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Solution for 3x-4(2x-3)=2(2x+1)+6 equation: 



3x-4(2x-3)=2(2x+1)+6

We move all terms to the left:

3x-4(2x-3)-(2(2x+1)+6)=0

We multiply parentheses

3x-8x-(2(2x+1)+6)+12=0



We calculate terms in parentheses: -(2(2x+1)+6), so:

2(2x+1)+6

We multiply parentheses

4x+2+6

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

-5x-(4x+8)+12=0

We get rid of parentheses

-5x-4x-8+12=0

We add all the numbers together, and all the variables

-9x+4=0

We move all terms containing x to the left, all other terms to the right

-9x=-4

x=-4/-9

x=4/9

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