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3x-4(2x-5)=2(x-1)
We move all terms to the left:
3x-4(2x-5)-(2(x-1))=0
We multiply parentheses
3x-8x-(2(x-1))+20=0
We calculate terms in parentheses: -(2(x-1)), so:We add all the numbers together, and all the variables
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
-5x-(2x-2)+20=0
We get rid of parentheses
-5x-2x+2+20=0
We add all the numbers together, and all the variables
-7x+22=0
We move all terms containing x to the left, all other terms to the right
-7x=-22
x=-22/-7
x=3+1/7
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