3x-4(2x-7)+12+13x=4(x+8)-2(2x)-(-24)

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Solution for 3x-4(2x-7)+12+13x=4(x+8)-2(2x)-(-24) equation: 



3x-4(2x-7)+12+13x=4(x+8)-2(2x)-(-24)

We move all terms to the left:

3x-4(2x-7)+12+13x-(4(x+8)-2(2x)-(-24))=0

We add all the numbers together, and all the variables

16x-4(2x-7)-(4(x+8)-22x-(-24))+12=0

We multiply parentheses

16x-8x-(4(x+8)-22x-(-24))+28+12=0



We calculate terms in parentheses: -(4(x+8)-22x-(-24)), so:

4(x+8)-22x-(-24)

We add all the numbers together, and all the variables

-22x+4(x+8)+24

We multiply parentheses

-22x+4x+32+24

We add all the numbers together, and all the variables

-18x+56

Back to the equation:

-(-18x+56)



We add all the numbers together, and all the variables

8x-(-18x+56)+40=0

We get rid of parentheses

8x+18x-56+40=0

We add all the numbers together, and all the variables

26x-16=0

We move all terms containing x to the left, all other terms to the right

26x=16

x=16/26

x=8/13

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