3x-4(3-2x)=4(x-5)-6

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Solution for 3x-4(3-2x)=4(x-5)-6 equation:



3x-4(3-2x)=4(x-5)-6
We move all terms to the left:
3x-4(3-2x)-(4(x-5)-6)=0
We add all the numbers together, and all the variables
3x-4(-2x+3)-(4(x-5)-6)=0
We multiply parentheses
3x+8x-(4(x-5)-6)-12=0
We calculate terms in parentheses: -(4(x-5)-6), so:
4(x-5)-6
We multiply parentheses
4x-20-6
We add all the numbers together, and all the variables
4x-26
Back to the equation:
-(4x-26)
We add all the numbers together, and all the variables
11x-(4x-26)-12=0
We get rid of parentheses
11x-4x+26-12=0
We add all the numbers together, and all the variables
7x+14=0
We move all terms containing x to the left, all other terms to the right
7x=-14
x=-14/7
x=-2

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