3x-4(3x+1)=2(-4x+5)-5

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Solution for 3x-4(3x+1)=2(-4x+5)-5 equation: 



3x-4(3x+1)=2(-4x+5)-5

We move all terms to the left:

3x-4(3x+1)-(2(-4x+5)-5)=0

We multiply parentheses

3x-12x-(2(-4x+5)-5)-4=0



We calculate terms in parentheses: -(2(-4x+5)-5), so:

2(-4x+5)-5

We multiply parentheses

-8x+10-5

We add all the numbers together, and all the variables

-8x+5

Back to the equation:

-(-8x+5)



We add all the numbers together, and all the variables

-9x-(-8x+5)-4=0

We get rid of parentheses

-9x+8x-5-4=0

We add all the numbers together, and all the variables

-1x-9=0

We move all terms containing x to the left, all other terms to the right

-x=9

x=9/-1

x=-9

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