3x-4(4-3x)=5(x-5)-21

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Solution for 3x-4(4-3x)=5(x-5)-21 equation: 



3x-4(4-3x)=5(x-5)-21

We move all terms to the left:

3x-4(4-3x)-(5(x-5)-21)=0

We add all the numbers together, and all the variables

3x-4(-3x+4)-(5(x-5)-21)=0

We multiply parentheses

3x+12x-(5(x-5)-21)-16=0



We calculate terms in parentheses: -(5(x-5)-21), so:

5(x-5)-21

We multiply parentheses

5x-25-21

We add all the numbers together, and all the variables

5x-46

Back to the equation:

-(5x-46)



We add all the numbers together, and all the variables

15x-(5x-46)-16=0

We get rid of parentheses

15x-5x+46-16=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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