3x-4(6-x)=3(5-2x)

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Solution for 3x-4(6-x)=3(5-2x) equation: 



3x-4(6-x)=3(5-2x)

We move all terms to the left:

3x-4(6-x)-(3(5-2x))=0

We add all the numbers together, and all the variables

3x-4(-1x+6)-(3(-2x+5))=0

We multiply parentheses

3x+4x-(3(-2x+5))-24=0



We calculate terms in parentheses: -(3(-2x+5)), so:

3(-2x+5)

We multiply parentheses

-6x+15

Back to the equation:

-(-6x+15)



We add all the numbers together, and all the variables

7x-(-6x+15)-24=0

We get rid of parentheses

7x+6x-15-24=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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