3x-4(7x-4)=2(6+4x)+4

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Solution for 3x-4(7x-4)=2(6+4x)+4 equation: 



3x-4(7x-4)=2(6+4x)+4

We move all terms to the left:

3x-4(7x-4)-(2(6+4x)+4)=0

We add all the numbers together, and all the variables

3x-4(7x-4)-(2(4x+6)+4)=0

We multiply parentheses

3x-28x-(2(4x+6)+4)+16=0



We calculate terms in parentheses: -(2(4x+6)+4), so:

2(4x+6)+4

We multiply parentheses

8x+12+4

We add all the numbers together, and all the variables

8x+16

Back to the equation:

-(8x+16)



We add all the numbers together, and all the variables

-25x-(8x+16)+16=0

We get rid of parentheses

-25x-8x-16+16=0

We add all the numbers together, and all the variables

-33x=0

x=0/-33

x=0

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